find the remainder when x cube minus 3 X square + 3 x minus 1 is divided by X + 3
Math
radhavyas
Question
find the remainder when x cube minus 3 X square + 3 x minus 1 is divided by X + 3
1 Answer

1. User Answers Brainly100
GIVEN
[tex]p(x) = {x}^{3}  3 {x}^{2} + 3x  1[/tex]
[tex]g(x) = x + 3[/tex]
TO FIND : Remainder of P(x) ÷ g(x)
SOLUTION
We can solve it by division algorithm as given in the attachment.
But we can go for Remainder Theorem for such questions :
By remainder Theorem we have to find zero of g(x)
g(x) = x + 3
=> x + 3 = 0
=> x = 3
We have to simply insert the value of x in p(x) to get the remainder :
P(x) = x^3  3x^2 + 3x  1
p(  3) = (  3)^3  3 × (3)^2 + 3 × 3 1
=  27  3 × 9  9 1
=  27  27  9 1
=  64
Hence the remainder is 64.